Published by:
CGP EDU Academic Team
Published on: August 11, 2026
SECTION 3 (Maximum Marks : 12)
• This section contains TWO paragraphs
• Based on each table, there are TWO questions
• Each question has FOUR options
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i)
W b =CV 0 xV 0

Heat dissipated = W b -E c or E c = E D =
CV 0 2
(ii)©
If capacitor is charged from V i to V f ; heat dissipated is



Total heat dissipated


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E D
and maintained for a charging time T>>RC. Then the voltage is raised to
without discharging the capacitor and again maintained for time T >>RC. The process is repeated one more time by raising the voltage to V 0 and the capacitor is charged to the same final voltage V 0 as in Process 1. These two processes are depicted in Figure 2.
(i) In Process 1, the energy stored in the capacitor E C and heat dissipated across resistance E D are released by: E C =2E D (ii) In Process 2, total energy dissipated across the resistance E D is: